Dev.to
Merge multiple docs into one in Google Docs
Originally written for bulldo.gs — republished here with the canonical link pointing home. I want to programmatically combine several Google Docs into one file without losing tables or list formatting. // Merges all source docs into destDocId, in order. // Run from the Apps Script editor; no triggers needed. function mergeDocs () { var sourceIds = [ ' DOC_ID_ONE ' , ' DOC_ID_TWO ' , ' DOC_ID_THREE ' ]; var dest = DocumentApp . openById ( ' DEST_DOC_ID ' ). getBody (); for ( var i = 0 ; i < sourceIds . length ; i ++ ) { var srcBody = DocumentApp . openById ( sourceIds [ i ]). getBody (); var total = srcBody . getNumChildren (); for ( var j = 0 ; j < total ; j ++ ) { var el = srcBody . getChild ( j ); var type = el . getType (); if ( type === DocumentApp . ElementType . PARAGRAPH ) { dest . appendParagraph ( el . asParagraph (). copy ()); } else if ( type === DocumentApp . ElementType . TABLE ) { dest . appendTable ( el . asTable (). copy ()); } else if ( type === DocumentApp . ElementType . LIST_ITEM ) { dest . appendListItem ( el . asListItem (). copy ()); } } } } Why there is no single appendElement call The Document service in Apps Script does not expose a generic appendElement method on Body . Every element type has its own typed append method: appendParagraph , appendTable , appendListItem , and so on. That means a merge loop that ignores element types will throw TypeError: el.copy is not a function the moment it hits a table, because you would be passing an Element where the API expects a Table . The fix is to call getType() on each child element and switch on DocumentApp.ElementType . The type enum values are strings like PARAGRAPH , TABLE , LIST_ITEM , INLINE_IMAGE , and HORIZONTAL_RULE . In practice the first three account for almost all real document content. The code above handles those three and silently skips anything else (images, rules) rather than crashing the entire merge. Getting the doc IDs and running the script The ID for any Google Doc is the lo
bulldo.gs
2026-06-13 08:35
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Dev.to
Remove duplicate rows in Google Sheets
Originally written for bulldo.gs — republished here with the canonical link pointing home. I have a Google Sheet with duplicate rows and I want to remove them programmatically, either on demand or on a schedule, without destroying the rest of my data. // removeDuplicates.gs — dedup active sheet, keep first occurrence // Run from Extensions > Apps Script, or bind to a trigger. function removeDuplicateRows () { var sheet = SpreadsheetApp . getActiveSheet (); var data = sheet . getDataRange (). getValues (); var seen = new Set (); var unique = []; for ( var i = 0 ; i < data . length ; i ++ ) { var key = data [ i ]. join ( ' | ' ); if ( ! seen . has ( key )) { seen . add ( key ); unique . push ( data [ i ]); } } sheet . clearContents (); sheet . getRange ( 1 , 1 , unique . length , unique [ 0 ]. length ). setValues ( unique ); } Why rewrite instead of delete The instinct when deduplicating is to loop through the sheet and call deleteRow on each duplicate. That works, but it has a sharp edge: every call to deleteRow shifts all rows below it up by one. If you delete row 3, what was row 4 is now row 3, and your loop index is already pointing at the new row 4. The safe workaround people reach for is iterating bottom-to-top, which works but means holding the full duplicate set in memory anyway, making one API call per deleted row. The approach here sidesteps the problem entirely. Read everything once with getDataRange().getValues() — a single API call that returns a 2D array. Build the deduplicated array in JavaScript using a Set to track which row fingerprints you have already seen. Then clear the sheet and write the result back with one setValues call. Two API calls total, regardless of how many duplicates you had. For a 10,000-row sheet, this is the difference between a script that finishes in two seconds and one that times out at the six-minute Apps Script execution limit. The row key is built with data[i].join('|'). The pipe character works as a separator in practice; i
bulldo.gs
2026-06-13 08:22
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Reddit r/programming
What Do Engineers Mean When We Say "Taste"?
submitted by /u/funnybong [link] [留言]
/u/funnybong
2026-06-13 07:17
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Reddit r/programming
Demystifying C++: Overcome the Fear of Memory Management in Minutes
submitted by /u/derjanni [link] [留言]
/u/derjanni
2026-06-13 04:28
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NomNak
Find restaurants through people you trust Discussion | Link
Matthew Hefferon
2026-06-13 03:35
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