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The OpenAI loop tests a view on AI, not just your coding bar

Canonical: this is a cross-post. The original lives at https://four-leaf.ai/blog/openai-interview-process Most OpenAI interview prep hands you a list of hard coding problems and tells you to grind. That calms the nerves and misreads the loop, because at OpenAI the coding bar sits next to something the grind can't touch: a genuine point of view on where AI is going and how it could go wrong. Candidate-facing guides describe that thread running from the first recruiter call to the final behavioral round. You can solve every problem and still stall if you can't hold that conversation. We've mapped the loops at Amazon , Google , Apple , Meta , and Bloomberg by reading each process through how the company actually runs. The map now includes the other AI labs and high-growth names candidates weigh alongside it, including Anthropic , SpaceX , and Robinhood . OpenAI is the one candidates most often prepare for as if it were a standard FAANG gauntlet. It isn't. The coding is practical rather than puzzle-flavored, a whole round asks you to present and defend work you built, and the loop varies more team to team than almost any large employer. Generic big-tech prep leaves you exposed on exactly the parts specific to OpenAI. A note on sourcing. OpenAI doesn't publish its interview process. There's no stage list, no scoring rubric, no candidate-facing equivalent of Google's structured-interviewing guidance. So this map comes from reputable secondary sources that collect named and dated candidate accounts, primarily interviewing.io's OpenAI question guide and Exponent's OpenAI software engineer guide . Where those accounts agree, this guide states the pattern. Where the loop varies or the record thins out, it says so rather than inventing detail. Treat everything below as the common shape, not a guaranteed sequence. Why the loop varies so much Start with the thing that makes OpenAI different to prep for. Hiring is decentralized, and secondary guides are blunt that the loop varies

2026-08-04 原文 →
AI 资讯

LLD Data Structures in Design Context: Stack — Understanding Last In, First Out Through Design

"A Stack isn't designed to store data. It's designed to make the most recent piece of work the easiest to access." In the previous article, we discovered a new kind of design problem. Some systems don't need to find the fastest item. Some don't need to process tasks in arrival order. Instead, they need to work with whatever happened most recently . That's exactly the problem a Stack solves. In this article, we'll understand how a Stack works and why its behavior appears naturally in many software systems. Imagine a Stack of Plates Think about a stack of dinner plates. Plate 4 ────────── Plate 3 ────────── Plate 2 ────────── Plate 1 ────────── When you need a plate, which one do you take? The one on the top. You don't pull out the bottom plate. Likewise, when placing a new plate, you put it on top. This simple rule defines the behavior of a Stack. What Is a Stack? A Stack is a data structure where both insertion and removal happen from the same end. The last item added is always the first one removed. This behavior is called LIFO (Last In, First Out). Push A ↓ Push B ↓ Push C ↓ Pop ↓ C Notice something important. A Stack isn't trying to preserve arrival order like a Queue. Instead, it preserves recency . The newest item is always the easiest to access. Every Data Structure Solves a Different Design Problem By now, we've seen several data structures, each answering a different question. A HashMap asks: Where is this object? A Heap asks: Which item has the highest priority? A Queue asks: Which task has been waiting the longest? A Stack asks: What happened most recently? Choosing the right data structure begins with identifying which of these questions your system needs to answer. Push and Pop Stacks are built around two simple operations. Push Adding a new item. Before Top ↓ B ↓ A Push C After Top ↓ C ↓ B ↓ A Pop Removing the most recent item. Before Top ↓ C ↓ B ↓ A Pop After Top ↓ B ↓ A Only the top item is removed. Everything below remains untouched. Real-World Examp

2026-08-04 原文 →
开发者

JavaScript Interview Questions Every Dev Should Know — Part 2: Functions, Scope & Closures

Welcome to Part 2 of the JS interview series! This time we're tackling functions, scope, and the topic that trips up even experienced developers in interviews: closures . Missed Part 1? Check out Fundamentals & Data Types first. Q1. What is a closure? A closure is what happens when an inner function "remembers" and continues to have access to the variables from its enclosing (outer) function's scope, even after that outer function has already finished running and would normally have had its local variables cleaned up. This works because JavaScript functions don't just capture the values of outer variables — they capture live references to them, keeping the entire surrounding scope alive in memory for as long as the inner function itself is reachable. Closures are one of the most powerful and commonly used patterns in JavaScript. They're the mechanism behind data privacy (since variables inside a closure can't be accessed from outside except through the functions that were given access), factory functions that generate customized functions, memoization caches, and event handler callbacks that need to remember state from when they were created. In the classic counter example below, each call to counter() creates a fresh, independent count variable that only the returned function can see or modify — there's no way to reach into it from outside. function counter () { let count = 0 ; return () => ++ count ; } const inc = counter (); inc (); // 1 inc (); // 2 Q2. What is lexical scoping? Lexical scoping (also called static scoping) means that a variable's accessibility is determined entirely by where it's physically written in your source code — not by which function called which, or the order in which functions happen to execute at runtime. When JavaScript compiles your code, it can already determine, just by looking at the nesting of functions and blocks, exactly which variables any given piece of code will be able to see. This is what allows an inner function to "reach

2026-08-04 原文 →
AI 资讯

30 technical interview questions, explained the way you'd actually say them

30 Technical Interview Questions You Should Be Able to Explain Out Loud (JS / React / Node) Most interview prep content gives you a definition. Real interviews test something different: can you explain your reasoning clearly, out loud, under a little pressure — not just recite the right words. I put together 30 questions across JavaScript, React, and Node.js. Every answer here is written the way you'd actually say it in an interview, not the way a textbook would write it. How to actually use this: cover the answer, try explaining it out loud in under 30 seconds, then read the answer. If you froze or rambled, that's the real signal — more than whether you technically knew the concept. JavaScript Fundamentals 1. What's a closure, and why does it actually matter in real code? A closure is a function that remembers the variables from where it was created, even after that outer function has finished running. It powers private variables, debouncing, memoization, and module patterns. 2. setTimeout(fn, 0) vs Promise.then() — which runs first? The Promise wins. .then() callbacks go into the microtask queue, which fully drains before the next macrotask (like setTimeout ) runs — even with a 0ms delay. 3. Why does var break inside loops with closures, but let doesn't? var is function-scoped — every iteration shares the same variable. let is block-scoped, so each iteration gets its own fresh binding. 4. Where does == actually give you a different (and wrong) answer than === ? == does type coercion first — 0 == false and '' == 0 are both true. === compares type and value directly, no surprises. 5. Why does this break in callbacks with regular functions, but not arrow functions? Regular functions get this based on how they're called. Arrow functions inherit this lexically from where they were defined, so it stays consistent no matter how they're invoked. 6. If a property isn't on an object, where does JS look next? JS walks the prototype chain — the object, then its prototype, the

2026-08-03 原文 →
开发者

Angela Nissel faces down grief with a laugh

Angela Nissel's latest book, Good Grief, Pass the Bread, Mom Is Dead, is my kind of memoir. Sure, it's a deeply emotional tale about caring for a terminally ill parent. But it's delivered with the sort of gallows humor that I often turn to to get me through tough times. Of course, that sort of […]

2026-08-02 原文 →
AI 资讯

LLD Data Structures in Design Context: The Heap Property — The Simple Rule That Makes Heaps Powerful

"A Heap doesn't stay useful because everything is sorted. It stays useful because every parent follows one simple rule." In the previous article, we learned that a Heap is built for continuous decision-making. Whether it's assigning the nearest driver, scheduling the next process, or selecting the most urgent support ticket, the system always needs one thing: The next best candidate But that raises an interesting question. How can a Heap always know the best candidate without sorting everything? The answer lies in one simple rule: The Heap Property. This single rule is what gives a Heap its power. The Biggest Misconception About Heaps Many beginners imagine a Heap like this. 100 95 90 82 76 64 51 Everything perfectly sorted. It feels logical. If the largest element should always come first, shouldn't every element be arranged in order? Surprisingly, no. A Heap solves a much smaller problem. It only guarantees that the best element is always easy to reach . Everything else only needs to follow one simple relationship. Imagine a Company Hierarchy Think about the structure of a company. CEO ↓ Engineering Director ↓ Engineering Manager ↓ Software Engineer The CEO doesn't directly manage every employee. Instead, each manager is responsible only for the people immediately below them. The entire organization works because every manager fulfills their local responsibility. A Heap works in a very similar way. Every node only needs to maintain the correct relationship with its immediate children. It doesn't need to know about every other node in the structure. The Heap Property Let's look at a Max Heap. 100 / \ 90 80 / \ / \ 75 60 70 50 Notice the pattern. Every parent has a value greater than or equal to its children. That's the Heap Property. Parent ≥ Children That's it. There is no rule saying that every node must be greater than every other node in the Heap. Only the parent-child relationship matters. What About a Min Heap? Some systems want the smallest value first. For

2026-08-01 原文 →
AI 资讯

LLD Data Structures in Design Context: Heap — A Data Structure Built for Continuous Decision Making

"A HashMap helps you find what you already know. A Heap helps you decide what should happen next." In the previous article, we discovered that not every software problem is about finding a specific object. Sometimes, the system already knows exactly what it's looking for. Find User ID = 1024 ↓ Return User Other times, the system doesn't know the answer in advance. Instead, it has to repeatedly answer questions like: Which task should run next? Which driver should be assigned? Which customer should be served first? Which alert is the most critical? These are fundamentally different problems. Instead of retrieving an object, the system is making a decision. This is where a Heap comes in. A Heap Is Built for Decisions, Not Searches Imagine you're managing a hospital emergency room. Patients keep arriving throughout the day. Patient A Minor Injury Patient B Heart Attack Patient C Broken Arm Patient D High Fever Should doctors treat patients in the order they arrived? Probably not. Instead, they ask one question. Who needs treatment first? Notice something important. The hospital isn't searching for a particular patient. It's choosing the highest-priority patient. A Heap is designed for exactly this kind of problem. A Different Way of Thinking When beginners hear "data structure," they often think about storing data. Experienced engineers think differently. They ask: "What operation does my system perform repeatedly?" If the answer is: Find User Find Order Find Product that's a lookup problem. But if the answer is: Choose Highest Priority Choose Nearest Driver Choose Earliest Deadline that's a decision problem. A Heap is optimized for continuous decision-making. What Exactly Is a Heap? A Heap is a data structure that keeps the most important element immediately available. Depending on the system, "most important" can mean different things. For example: Highest priority Lowest cost Earliest deadline Highest score Closest driver Most urgent ticket The Heap doesn't decide w

2026-08-01 原文 →
AI 资讯

LLD Data Structures in Design Context: Why Some Problems Need the "Best" Result Instead of Any Result

"Finding something quickly and finding the best thing quickly are two completely different engineering problems." So far in this series, we've explored one of the most common behaviours in software systems: Fast lookup. Whenever a system already knows what it's looking for—a User ID, Product ID, Order ID or Session ID—a HashMap becomes an excellent choice. But not every software problem works this way. Imagine you're building a ride-sharing application. A rider requests a cab. The system doesn't already know which driver to assign. Instead, it must answer a different question: "Out of all available drivers, who is the best choice?" Now consider a task scheduler. Hundreds of jobs are waiting to run. The scheduler doesn't ask: "Find Job #123." It asks: "Which job should run next?" Or imagine a gaming platform. Thousands of players are competing. Nobody asks: "Find Player ID 1057." Instead, users ask: "Who are the top 10 players?" These problems are fundamentally different from fast lookup. They're not about finding a specific object . They're about finding the best object according to some priority. This shift in thinking introduces another important design behaviour. Fast Lookup vs Best Selection Let's compare two different requirements. Requirement 1 Customer ID = 1052 ↓ Retrieve Customer The system already knows exactly what it needs. The challenge is retrieving it efficiently. Requirement 2 Available Drivers ↓ Find Nearest Driver ↓ Assign Ride The system doesn't know the answer yet. It must compare multiple candidates before making a decision. These two behaviours may look similar. In reality, they solve completely different engineering problems. Every Software System Doesn't Search the Same Way Consider these questions. Find Order #50231 versus Find the highest priority order. Or: Retrieve Product ID = P1042 versus Recommend the most popular product. Or: Find Employee ID = 2107 versus Find the employee with the highest sales this month. The first question always

2026-08-01 原文 →
AI 资讯

"Kubernetes Interviews Are Broken When Trivia Matters More Than Real Skill"

Kubernetes Interviews Are Broken When Trivia Matters More Than Real Skill Kubernetes interviews often fail when they test whether a candidate can recall obscure implementation details instead of showing how that person diagnoses failures, reasons through tradeoffs, and learns under pressure. Certifications can prove useful baseline knowledge, but neither a certificate nor a perfect whiteboard answer reliably proves that someone can operate a production cluster. The frustration becomes obvious when an interview demands a kernel level explanation of what happens when traffic reaches an ingress controller in a Cilium based, proxyless setup, while the actual role may involve changing a CPU request from 500m to 550m. The contrast is funny because it feels painfully familiar. Candidates prepare for architecture, networking, controllers, scheduling, and troubleshooting, then get judged on a detail they could verify in seconds during real work. That does not mean deep technical knowledge is useless. Some roles genuinely require it. The problem begins when interview difficulty becomes disconnected from job difficulty, and when memorization is treated as a shortcut for measuring engineering judgment. Why Kubernetes interview questions feel disconnected from the job The strongest complaint in the discussion was not that Kubernetes is too difficult. It was that many interview questions appear designed to establish superiority rather than measure readiness for the role. One example captured the problem perfectly: the interview asks for a detailed explanation of kernel behavior, ingress traffic, Cilium, eBPF, and proxyless networking. The work itself turns out to be a minor resource adjustment. That gap creates distrust because candidates are being filtered through a standard that the daily job may never require. A technical interview should reflect the decisions the engineer will actually make. If the job involves operating clusters, useful questions might examine how the candid

2026-08-01 原文 →
AI 资讯

LLD Data Structures in Design Context: How Does a HashMap Find the Right Location? Understanding Hashing Without the Math

"The real magic of a HashMap isn't that it stores data. It's that it knows where to start looking." In the previous article, we learned that a HashMap organises information around unique keys. Instead of searching every stored object one by one, it uses the key to retrieve information quickly. That naturally raises another question. "If millions of objects are stored inside a HashMap, how does it know where to begin?" Surely it isn't remembering the location of every object individually. The answer lies in one of the most important ideas in computer science: Hashing. Don't worry if the word sounds intimidating. Despite its name, the idea behind hashing is surprisingly simple. Imagine a Huge Apartment Building Suppose you're visiting a friend who lives in a building with 5,000 apartments. If nobody told you the apartment number, what would you do? Probably something like this. Apartment 1 ↓ Apartment 2 ↓ Apartment 3 ↓ ... ↓ Friend's Apartment That would take a long time. Now imagine your friend simply tells you: Apartment 1842 Suddenly, you don't search the building. You walk directly to Apartment 1842. The apartment number isn't your friend. It simply tells you where to begin. Hashing works in exactly the same way. Keys Need Locations Suppose our application stores customers. Customer ID → Customer 1001 → Alice 1002 → Bob 1003 → Charlie 1004 → David The system needs a way to answer one question. "Where should Customer 1002 be stored?" Searching every location first would defeat the purpose of using a HashMap. Instead, the system calculates where that key should go. Notice something important. It doesn't compare Customer 1002 against every other customer. It calculates a location directly. Think of a School Locker System Imagine a school with thousands of students. Every student receives a locker. Student ID ↓ Locker Number ↓ Locker Students don't spend every morning searching hundreds of lockers. Their Student ID determines where they should go. The locker number is

2026-07-30 原文 →
AI 资讯

LLD Data Structures in Design Context: Why Great Software Starts with Behaviours, Not Data Structures

"The best software engineers don't begin by choosing data structures. They begin by understanding what the system needs to do." In the previous article, we learned that data structures never stopped being important after DSA. Their role simply changed. During coding interviews, we often ask ourselves: "Which data structure will solve this problem efficiently?" In Low-Level Design, experienced engineers ask a different question: "What behaviour should this system optimise?" At first glance, these questions sound similar. In reality, they lead to completely different ways of thinking. This article is about understanding why behaviour—not implementation—is where every good design begins. Why Beginners Often Think About Data Structures Too Early Imagine someone asks you to design an online food delivery platform. Many beginners immediately start thinking: Should I use a HashMap? Will I need a Queue? Should I store everything in a Tree? Would a Graph be useful? These aren't bad questions. They're simply being asked too early. Before choosing any data structure, we need to understand what the system is actually expected to do. Software engineering isn't about selecting tools first. It's about understanding problems first. Every Software System Is Really a Collection of Behaviours Let's consider a food delivery application. From a user's perspective, it looks like this. Customer Places Order │ Restaurant Accepts │ Assign Delivery Partner │ Track Delivery │ Order Delivered It looks like one workflow. But an engineer sees something very different. Each step represents a different behaviour. Let's break them apart. Behaviour 1 — Retrieve Existing Information A customer opens an order they placed yesterday. Customer ↓ Order ID ↓ Retrieve Order The system already knows exactly which order it needs. The challenge is retrieving it quickly. Behaviour 2 — Choose the Best Candidate A restaurant has multiple delivery partners nearby. Available Drivers ↓ Choose Best Driver ↓ Assign Ri

2026-07-29 原文 →
AI 资讯

Presentation: Getting Rid of LeetCode Interviews in the World of AI

Daniel Doubrovkine explains why traditional LeetCode whiteboard interviews fail to evaluate senior engineering talent. He discusses his own experience bombing basic algorithm tests despite decades of leadership, and shares actionable frameworks for redefining the interview loop. Discover how evaluating human judgment, system design, and hands-on AI collaboration yields far better hiring signals. By Daniel Doubrovkine

2026-07-29 原文 →
AI 资讯

JavaScript Type Coercion — Output-Based Questions ([] + [], NaN === NaN & Friends)

After hoisting, interviewers love dropping one-liners like: console . log ([] + []); console . log ([] + {}); console . log ({} + []); console . log ( NaN === NaN ); …and watching whether you guess, freeze, or calmly walk the coercion rules. This post is only output-based type coercion / equality questions. Try each snippet yourself first. Answers are hidden — click Show answer when you’re ready. TL;DR — what interviewers are testing Concept Trap + with objects/arrays Often becomes string concat , not math [] / {} stringification [] → "" , {} → "[object Object]" Bare {} + [] Parser may treat {} as a block , not an object NaN === NaN Always false — use Number.isNaN / Object.is == vs === == coerces; === does not Falsy vs “empty-looking” [] and {} are truthy typeof null Infamous "object" lie One-line mental model + asks both sides to become primitives. If either side is a string (after that), you get concatenation . Otherwise you get number math — and weird values become NaN . Warm-up: how + really decides When JS hits a + b , it roughly does: 1) Convert both sides to primitives (ToPrimitive) 2) If either result is a string → String(a) + String(b) // concat 3) Else → Number(a) + Number(b) // math For plain objects / arrays, ToPrimitive usually ends up calling .toString() : Value String(value) Number(value) [] "" 0 [1, 2] "1,2" NaN {} "[object Object]" NaN null "null" 0 undefined "undefined" NaN true "true" 1 false "false" 0 That’s enough to solve most [] + {} style questions. How to use this post Read the snippet Say the output out loud (or write it down) Only then open Show answer Read the step-by-step — don’t only memorize the final print Q1 — Classic [] + [] console . log ([] + []); Show answer Output "" (empty string — looks like a blank line) Step by step + wants primitives from both arrays. String([]) → "" (empty array joins to empty string). "" + "" → "" . Interview tip: People often say 0 or [] . Wrong. Empty array stringifies to "" , so you get string concat o

2026-07-26 原文 →
开发者

Synth historian Oli Freke will spend big on a good bicycle

Oli Freke is a musician and journalist whose works have appeared in Sound on Sound, The Quietus, and Mixmag. This has included using math to explore the melodic potential of the Western 12-tone scale and deep dives on effects plug-ins. He's even written a book tracing the evolution of the synthesizer from 1963 through 1995, […]

2026-07-25 原文 →
开发者

I Found the LeetCode for System Design Interview, and It's Awesome

Disclosure: This post includes affiliate links; I may receive compensation if you purchase products or services from the different links provided in this article. Credit: codemia.io Hello Devs, if you're preparing for software engineering interviews, particularly in MAANG, you already know that Data Structures & Algorithms (DSA) and System Design are two key areas where you will be rigorously tested. While LeetCode is the go-to platform for DSA, system design has always been a challenge. While there are many websites and platforms to prepare for System Design Interviews like ByteByteGo , DesignGurus.io , Exponent , Educative , and Udemy , there is nothing like LeetCode. These are great resources to learn fundamentals, go through case studies, and understand the theory part of system design, but LeetCode-style practice is one thing that is missing - until now. I recently found Codemia.io , and I must say, it feels like the LeetCode for System Design. If you've struggled with structuring your system design answers, getting real feedback, or knowing whether your approach is correct, Codemia.io is a game-changer. They not only have the biggest collection of System Design and OOP Design problems for practice, but they also have a free System Design course called Tackling System Design Interview Problems , which is a great free resource to learn essential System Design concepts. It's a short course with 2 hours of content, but it's powerful and also has quizzes to test your skills. Here are all the key System Design topics you can learn on this free course: Now, let's check out how Codemia.io can help you to prepare better for your System design and OOP Design interview, and why I think it's like Leetcode for System design. Most system design resources today are long, text-heavy articles or expensive courses. The problem? No hands-on practice - Reading about system design isn't enough; you need to actively design solutions. No structured progression --- Unlike DSA, where

2026-07-25 原文 →
AI 资讯

Back-of-the-envelope estimation for system design interviews

Back-of-the-envelope estimation for system design interviews Most people don't fail capacity math because the arithmetic is hard. They fail because they do it silently, produce a number they can't defend, and then never use it again for the rest of the interview. The math itself is trivial. The method is what's worth learning. Why interviewers ask Capacity estimation isn't a numeracy test. It's checking two things: Can you tell whether a design is physically possible before you commit to it? Do you know which constraint actually binds — storage, read throughput, write throughput, or bandwidth? A candidate who estimates 30,000 reads/sec and 200 writes/sec has learned something that changes the design. A candidate who computes petabytes of storage and then never mentions it again has just performed arithmetic. Round aggressively Precision is a trap. You're not producing a capacity plan; you're finding the order of magnitude. The single most useful substitution: 1 day = 86,400 seconds ≈ 10^5 seconds That's a 16% error and it makes every subsequent division doable in your head. Nobody will challenge it. Everyone will notice if you spend forty seconds long-dividing by 86,400. A few more worth having ready: 1 million requests/day ≈ 12/sec — round to 10 1 KB × 1 million = 1 GB 1 KB × 1 billion = 1 TB Peak traffic ≈ 2–3× average Replicated storage ≈ 3× raw ## Work in one direction Users → requests → QPS → storage → bandwidth. Don't jump around. Say each assumption out loud and label it as an assumption, so the interviewer can correct you early rather than watch you build on sand. A worked example Say we're designing a social feed. Given: 100M daily active users. Assumptions (stated, not smuggled in): Each user posts 0.2 times/day Each user reads their feed 10 times/day A post averages 1 KB including metadata A feed page shows 20 posts Writes 100M × 0.2 = 20M posts/day 20M / 10^5 = 200 writes/sec Peak (3×) = 600 writes/sec Reads 100M × 10 = 1B feed loads/day 1B / 10^5 = 10,0

2026-07-24 原文 →